资源简介
用MATLAB编写SDES代码,用于简单说明DES加密原理的小实验。
代码片段和文件信息
clearclc
%输入明文M和密钥K
M=input(‘输入16位字符明文:‘)
K=input(‘输入16位字符密文:‘)
% M=[‘0‘ ‘1‘ ‘2‘ ‘3‘ ‘4‘ ‘5‘ ‘6‘ ‘7‘ ‘8‘ ‘9‘ ‘A‘ ‘B‘ ‘C‘ ‘D‘ ‘E‘ ‘F‘];
% K=[‘0‘ ‘1‘ ‘2‘ ‘3‘ ‘4‘ ‘5‘ ‘6‘ ‘7‘ ‘8‘ ‘9‘ ‘A‘ ‘B‘ ‘C‘ ‘D‘ ‘E‘ ‘F‘];
%% ---------------第一步:数据初始化--------------------------------
%以字符串形式输入的明文和密钥转换成01数字串
MB=[];
for i=1:16
Mi=M(i);
MBi=[‘0000‘dec2bin(hex2dec(Mi))];
MBi=MBi(end-3:end);
MBi=[str2num(MBi(1))str2num(MBi(2))str2num(MBi(3))str2num(MBi(4))];
MB=[MBMBi];
end
M=MB;
KB=[];
for i=1:16
Ki=K(i);
KBi=[‘0000‘dec2bin(hex2dec(Ki))];
KBi=KBi(end-3:end);
KBi=[str2num(KBi(1))str2num(KBi(2))str2num(KBi(3))str2num(KBi(4))];
KB=[KBKBi];
end
K=KB;
E=[32 1 2 3 4 5;
4 5 6 7 8 9;
8 910111213;
121314151617;
161718192021;
202122232425;
242526272829;
28293031321];
S1=[14 4 13 1 2 15 11 8 3 10 6 12 5 9 0 7;
0 15 7 4 14 2 13 1 10 6 12 11 9 5 3 8;
4 1 14 8 13 6 2 11 15 12 9 7 3 10 5 0;
15 12 8 2 4 9 1 7 5 11 3 14 10 0 6 13];
S2=[15 1 8 14 6 11 3 4 9 7 2 13 12 0 5 10;
3 13 4 7 15 2 8 14 12 0 1 10 6 9 11 5;
0 14 7 11 10 4 13 1 5 8 12 6 9 3 2 15;
13 8 10 1 3 15 4 2 11 6 7 12 0 5 14 9];
S3=[10 0 9 14 6 3 15 5 1 13 12 7 11 4 2 8;
13 7 0 9 3 4 6 10 2 8 5 14 12 11 15 1;
13 6 4 9 8 15 3 0 11 1 2 12 5 10 14 7;
1 10 13 0 6 9 8 7 4 15 14 3 11 5 2 12];
S4=[7 13 14 3 0 6 9 10 1 2 8 5 11 12 4 15;
13 8 11 5 6 15 0 3 4 7 2 12 1 10 14 9;
10 6 9 0 12 11 7 13 15 1 3 14 5 2 8 4;
3 15 0 6 10 1 13 8 9 4 5 11 12 7 2 14];
S5=[2 12 4 1 7 10 11 6 8 5 3 15 13 0 14 9;
14 11 2 12 4 7 13 1 5 0 15 10 3 9 8 6;
4 2 1 11 10 13 7 8 15 9 12 5 6 3 0 14;
11 8 12 7 1 14 2 13 6 15 0 9 10 4 5 3];
S6=[12 1 10 15 9 2 6 8 0 13 3 4 14 7 5 11;
10 15 4 2 7 12 9 5 6 1 13 14 0 11 3 8;
9 14 15 5 2 8 12 3 7 0 4 10 1 13 11 6;
4 3 2 12 9 5 15 10 11 14 1 7 6 0 8 13];
S7=[4 11 2 14 15 0 8 13 3 12 9 7 5 10 6 1;
13 0 11 7 4 9 1 10 14 3 5 12 2 15 8 6;
1 4 11 13 12 3 7 14 10 15 6 8 0 5 9 2;
6 11 13 8 1 4 10 7 9 5 0 15 14 2 3 12];
S8=[13 2 8 4 6 15 11 1 10 9 3 14 5 0 12 7;
1 15 13 8 10 3 7 4 12 5 6 11 0 14 9 2;
7 11 4 1 9 12 14 2 0 6 10 13 15 3 5 8;
2 1 14 7 4 10 8 13 15 12 9 0 3 5 6 11];
P=[1672021291228171152326518311028241432273919133062211425];
PC1=[57494133251791585042342618
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