资源简介
OFDM的编码类技术降低系统峰均比。PTS作为其中一种,占有重要作用。此程序仿真了降低PAPR的性能
代码片段和文件信息
clear all; clc; close all;
K = 128; % SIZE OF FFT
V = 4; % NUMBER OF SELECTIONS
QPSK_Set = [1 -1 j -j];
Phase_Set = [1 -1];
Choose = [1 1 1 1; 1 1 1 2; 1 1 2 1; 1 2 1 1; 2 1 1 1;...
1 1 2 2; 1 2 1 2; 1 2 2 1; 2 2 1 1; 2 1 2 1; 2 1 1 2;...
2 2 2 1; 2 2 1 2; 2 1 2 2; 1 2 2 2; 2 2 2 2];
Choose_Len = 16;
MAX_SYMBOLS = 1e5;
PAPR_Orignal = zeros(1MAX_SYMBOLS);
% original
for nSymbol=1:MAX_SYMBOLS
Index = randint(1Klength(QPSK_Set))+1;%1*128
X= QPSK_Set(Index(1:)); % Orignal Frequency domain signal
x = ifft(X[]2); %1*128 % Time domain signal
Signal_Power0 = abs(x.^2);
Peak_Power0 = max(Signal_Power0[]2);
Mean_Power0 = mean(Signal_Power02);
PAPR_Orignal(nSymbol) = 10*log10(Peak_Power0./Mean_Power0);
end
%随机交织+遍历搜索
PAPR_PTS1 = zeros(1MAX_SYMBOLS);
for nSymbol=1:MAX_SYMBOLS
Index1 = randint(1Klength(QPSK_Set))+1;
X1 = QPSK_Set(Index1(1:)); % Orignal Frequency domain signal
l1=length(X1);
z1=zeros(Vl1);
pilot1=randperm(l1/2);
for k1=1:V/2
z1(k1pilot1(k1:V/2:l1/2))=X1(pilot1(k1:V/2:l1/2));%随机
end
for k1=(V/2)+1:V
z1(k1k1-2+l1/2:V/2:l1)=X1(k1-2+l1/2:V/2:l1);%交织
end
a1= ifft(z1[]2);
min_value1 = 10;
for n1=1:Choose_Len
temp_phase1 = Phase_Set(Choose(n1:)).‘;
temp_max1 = max((abs(sum(a1.*repmat(temp_phase11K)))).^2);
if temp_max1 min_value1= temp_max1;
Best_n1 = n1;
end
end
aa1 = sum(a1.*repmat(Phase_Set(Choose(Best_n1:)).‘1K));
Signal_Power1 = abs(aa1.^2);
Peak_Power1 = max(Signal_Power1[]2);
Mean_Power1 = mean(Signal_Power12);
PAPR_PTS1(nSymbol) = 10*log10(Peak_Power1./Mean_Power1);
end
%随机分割+遍历搜索
PAPR_PTS4 = zeros(1MAX_SYMBOLS);
for nSymbol=1:MAX_SYMBOLS
Index4 = randint(1Klength(QPSK_Set))+1;
X4 = QPSK_Set(Index1(1:)); % Orignal Frequency domain signal
l4=length(X4);
A4= zeros(VK);
pilot4=randperm(l4);
for k=1:V
A4(kpilot4(k:V:l4))=X4(pilot4(k:V:l4));%随机
end
a4= ifft(A4[]2);
min_value4 = 10;
for n4=1:Choose_Len
temp_phase4= Phase_Set(Choose(n4:)).‘;
temp_max4= max(abs(sum(a4.*repmat(temp_phase41K))));
if temp_max4 min_value4= temp_max4;
Best_n4 = n4;
end
end
aa4= sum(a4.*repmat(Phase_Set(Choose(Best_n4:)).‘1K));
Signal_Power4= abs(aa4.^2);
Peak_Power4= max(Signal_Power4[]2);
Mean_Power4 = mean(Signal_Power42);
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