• 大小: 7KB
    文件类型: .m
    金币: 1
    下载: 0 次
    发布日期: 2021-06-16
  • 语言: Matlab
  • 标签: 下料问题  Matlab  

资源简介

绝对原创,效果非常好,所需种类55种,板子数799

资源截图

代码片段和文件信息

tic
clear all; clc
l = [1743 1680 1532 1477 1313 1285 1232 1217 1180 1177  1105 1055 1046 1032 1030 975 893 882 847 845 ...
    830 795 766 745 730 719 714 695 645 630 610 600 590 588 582 578 540 488 355 343 320 515 414 411 405 328 313 290 275 265 ...
    255 184 155 ];
n = [ 4 216 104 38 4 60 4 8 6 10  8 2 4 8 8 2 8 301 6 38 30 8 4 4 34 18 4 4 90 30 ...
     30 212 108 482 196 8 32 4 52 42  8 8 8 60 136 4 68 286 602 286   192 57 24];
% [lpai weizhi ] = sort(l‘descend‘);
% npai = n(weizhi);
% qing = [l ; n];
TotalLeft = 1:53; NLeft0 = n;  FourDay = [  5791215182025 283648]; SixDay = [ 41124293238404650 ]; YiYoLiao = 0; 
ChangeCostLv = .08*.01; FourDayLeft =  FourDay;  SixDayLeft =  SixDay;  NFourDayLeft = n(FourDay); NSixDayLeft = n(SixDay); 
WasteLiao = 0;   NumMax = 1; 

for jj = 1:NumMax
    TotalLeft = 1:53; NLeft = NLeft0(TotalLeft); ii = 0;
    ShengLiao = 3000; 
    Others = TotalLeft;
    ShengLiaoTotal = zeros(1length(Others));
    for i = 1:length(Others)
          lDangQian = l( Others(i) );  NumberOfPresent = 0; 
          ShengLiaoo = ShengLiao; 
          while ShengLiaoo >= lDangQian 
               if   ShengLiaoo < lDangQian + 5
                        ShengLiaoo = 0;
               else
                       ShengLiaoo = ShengLiaoo - lDangQian - 5;
                end
          end
               ShengLiaoTotal(i) = ShengLiaoo;
                  
      end
           
      [ShengLiaoTotal weizhi] = min(ShengLiaoTotal);
      ShengLiaoTotal = [];
      DangQian = Others(weizhi);  lDangQian = l(DangQian);  
      
     while  ~isempty(TotalLeft) 
          MoShi = [];
          ii = ii + 1; tt = 0; ShengLiao = 3000;
%           DangQian = TotalLeft(1);  lDangQian = l(DangQian);
          while ShengLiao >= lDangQian  
               if   ShengLiao < lDangQian + 5  
                    tt = tt + 1;
%                     NLeft(weizhi) = NLeft(weizhi) -1;
                     NLeft(weizhi) = NLeft(weizhi) -1;
                    ShengLiao = 0;
                    MoShi(tt) = DangQian;
               else 
                    tt = tt + 1;
%                     NLeft(weizhi) = NLeft(weizhi) -1;
                     NLeft(weizhi) = NLeft(weizhi) -1;
                    ShengLiao = ShengLiao - lDangQian - 5;
                    MoShi(tt) = DangQian;
                          
               end
               TotalLeft(NLeft==0) = [];
               NLeft(NLeft==0) = [];
               if  isempty(TotalLeft)
                   break;
               end
               
                Others = TotalLeft;
                for i = 1:length(Others)
                   lDangQian = l( Others(i) );  
                   ShengLiaoo = ShengLiao; 
                   while ShengLiaoo >= lDangQian 
                        if   ShengLiaoo < lDangQian + 5
                             ShengLiaoo = 0;
                        else
                            ShengLia

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