资源简介
DCT的动态模型,matlab主程序代码,
代码片段和文件信息
%DCT Dynamic Model
%Paul Walker
%30JAN08
function DCT_dynamic_Model_SD_V3a
%This program models the dynamic response of a DCT during transient shifts.
%This includes gear synchronisation as well as clutch to clutch shifting
%and launch of the vehicle. The model is stylised on a FWD vehicle.
%The model incoporates engine dynamics including torsional vibrations a
%basic DMFW for torsional damping simplified dual clutch transmission
%(including 2 clutches and 2 gear pairs with synchronisers which inclides
%reduced transmission inertia for the gears and drag torque for damping)
%final drive output shafts and wheel components.
clear all
%1.0 Model Parameters and Constants
%1.1 Constants & Initial Conditions
%1.1.1 Time constants - IGNORE
%1.1.2 Gears and transmission states
G1=3; %Selected gear for clutch 1
G2=4; %Selected gear for clutch 2
%1.1.3 Engine and Vehicle speeds - IGNORE
%1.2 Dynamic model parameters
%1.1.05 Common Properties
Gsm=80e9; %Shear modulus of steel (Pa)
rhosteel=787; %density of steel (kg/m3)
%1.2.1 Engine Model
Ie=0.4; %Engine inertia (kgm2)
De1=0.04; %Engine shaft OD (m)
De2=0.02; %Engine shaft ID (m)
Les=0.2; %engine shaft length
Ke=(pi*Gsm*(De1^4-De2^4)/(32*Les)); %Output shaft stiffness (Nm/rad)
%1.2.2 DMFW Parameters
Idm1=0.2; %First DMFW inertia (kgm2)
Idm2=0.2; %Second DMFW inertia (kgm2)
Kdm=2e5;%ie not DMFW with 2e5 700 %DMFW spring rate (Nm/rad)
mu1=0.12; %Friction coefficient for spring on housing
ms=1; %Mass of DMFW spring (kg)
rs=0.12; %Outer spring radius in housing (m)
Cdm=2;%2*mu1*ms*rs; %DMFW damping (Nmrad/s)
Thys=40; %constant hysteresis torque
%1.2.3 Transmission Parameters
%1.2.3.1 Clutch
%C1 corresponds to odd gears
%C2 corresponds to even gears
mus=0.16; %static friction
mud=0.14; %dynamic friction
nf=8; %number of friction surfaces
Ic1=0.0072;
if G1==1 || G2==1
Kc1=8e4;
elseif G1==3 || G2==3
Kc1=2.1e5;
else
Kc1=7e4;
end
Rc1o=163/2;
Rc1i=105/2;
Ac1=pi*(Rc1o^2-Rc1i^2);
Rm1=2/3*(Rc1o^3-Rc1i^3)/(Rc1o^2-Rc1i^2);
Ic2=0.0125;
if G1==2 || G2==2
Kc2=7e4;
else
Kc2=8.7e5;
end
Rc2o=193/2;
Rc2i=139/2;
Ac2=pi*(Rc2o^2-Rc2i^2);
Rm2=2/3*(Rc2o^3-Rc2i^3)/(Rc2o^2-Rc2i^2);
h1=0.1e-3; %Plate spacing (m)
%1.2.3.2 Gears and Synchronisers
Ip=[0.000074 0.00025 0.00056 0.0013 0.00096 0.0014]; %inertia of whole shaft and gearset (kgm2)
Ig=[0.0085 0.0049 0.0025 0.0014 0.0014 0.00085]; %approximated inertia of cylinders (kgm2)
GR=[3.45 2.05 1.45 1.08 1.11 0.92];
if G1==1 || G1==3
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